Getting block size via df vs dumpe2fs









up vote
2
down vote

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These two tools, seems to report different block sizes



root@ubuntu-xenial:~# df
Filesystem 1K-blocks Used Available Use% Mounted on
udev 498588 0 498588 0% /dev
tmpfs 101584 3116 98468 4% /run
/dev/sda1 10098468 1438288 8643796 15% /
tmpfs 507916 0 507916 0% /dev/shm
tmpfs 5120 0 5120 0% /run/lock
tmpfs 507916 0 507916 0% /sys/fs/cgroup
vagrant 343946960 55977016 287969944 17% /vagrant
tmpfs 101584 0 101584 0% /run/user/1000

root@ubuntu-xenial:~# dumpe2fs /dev/sda1 | grep -i block | grep -i size
dumpe2fs 1.42.13 (17-May-2015)
Block size: 4096
Flex block group size: 16


What is more, fdisk command reports different sector size (aren't the terms sector and block interchangeable?)



root@ubuntu-xenial:~# fdisk -l
Disk /dev/sda: 10 GiB, 10737418240 bytes, 20971520 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0x38d40272

Device Boot Start End Sectors Size Id Type
/dev/sda1 * 2048 20971486 20969439 10G 83 Linux


Disk /dev/sdb: 10 MiB, 10485760 bytes, 20480 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes


I am on a vagrant machine for what that matters







share|improve this question





















  • It would be much easier for people to write a specific answer, if you wrote out a specific sentence with a question mark :-). (You can create followup questions later if needed). blockdev can return three types of block sizes with different values. And grep -H . /sys/class/block/sda/queue/*_block,io_size shows the same 4 different types printed by fdisk. Is your question "Why is there a difference between these two commands?" Is it "how can I see the block size used to allocate space on my filesystem?" Are you looking into something different from space allocation?
    – sourcejedi
    14 hours ago











  • Is your question "What is the difference between the 4 sizes printed by fdisk?" So you can see there's a number of different questions you might have in mind.
    – sourcejedi
    14 hours ago















up vote
2
down vote

favorite












These two tools, seems to report different block sizes



root@ubuntu-xenial:~# df
Filesystem 1K-blocks Used Available Use% Mounted on
udev 498588 0 498588 0% /dev
tmpfs 101584 3116 98468 4% /run
/dev/sda1 10098468 1438288 8643796 15% /
tmpfs 507916 0 507916 0% /dev/shm
tmpfs 5120 0 5120 0% /run/lock
tmpfs 507916 0 507916 0% /sys/fs/cgroup
vagrant 343946960 55977016 287969944 17% /vagrant
tmpfs 101584 0 101584 0% /run/user/1000

root@ubuntu-xenial:~# dumpe2fs /dev/sda1 | grep -i block | grep -i size
dumpe2fs 1.42.13 (17-May-2015)
Block size: 4096
Flex block group size: 16


What is more, fdisk command reports different sector size (aren't the terms sector and block interchangeable?)



root@ubuntu-xenial:~# fdisk -l
Disk /dev/sda: 10 GiB, 10737418240 bytes, 20971520 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0x38d40272

Device Boot Start End Sectors Size Id Type
/dev/sda1 * 2048 20971486 20969439 10G 83 Linux


Disk /dev/sdb: 10 MiB, 10485760 bytes, 20480 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes


I am on a vagrant machine for what that matters







share|improve this question





















  • It would be much easier for people to write a specific answer, if you wrote out a specific sentence with a question mark :-). (You can create followup questions later if needed). blockdev can return three types of block sizes with different values. And grep -H . /sys/class/block/sda/queue/*_block,io_size shows the same 4 different types printed by fdisk. Is your question "Why is there a difference between these two commands?" Is it "how can I see the block size used to allocate space on my filesystem?" Are you looking into something different from space allocation?
    – sourcejedi
    14 hours ago











  • Is your question "What is the difference between the 4 sizes printed by fdisk?" So you can see there's a number of different questions you might have in mind.
    – sourcejedi
    14 hours ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











These two tools, seems to report different block sizes



root@ubuntu-xenial:~# df
Filesystem 1K-blocks Used Available Use% Mounted on
udev 498588 0 498588 0% /dev
tmpfs 101584 3116 98468 4% /run
/dev/sda1 10098468 1438288 8643796 15% /
tmpfs 507916 0 507916 0% /dev/shm
tmpfs 5120 0 5120 0% /run/lock
tmpfs 507916 0 507916 0% /sys/fs/cgroup
vagrant 343946960 55977016 287969944 17% /vagrant
tmpfs 101584 0 101584 0% /run/user/1000

root@ubuntu-xenial:~# dumpe2fs /dev/sda1 | grep -i block | grep -i size
dumpe2fs 1.42.13 (17-May-2015)
Block size: 4096
Flex block group size: 16


What is more, fdisk command reports different sector size (aren't the terms sector and block interchangeable?)



root@ubuntu-xenial:~# fdisk -l
Disk /dev/sda: 10 GiB, 10737418240 bytes, 20971520 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0x38d40272

Device Boot Start End Sectors Size Id Type
/dev/sda1 * 2048 20971486 20969439 10G 83 Linux


Disk /dev/sdb: 10 MiB, 10485760 bytes, 20480 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes


I am on a vagrant machine for what that matters







share|improve this question













These two tools, seems to report different block sizes



root@ubuntu-xenial:~# df
Filesystem 1K-blocks Used Available Use% Mounted on
udev 498588 0 498588 0% /dev
tmpfs 101584 3116 98468 4% /run
/dev/sda1 10098468 1438288 8643796 15% /
tmpfs 507916 0 507916 0% /dev/shm
tmpfs 5120 0 5120 0% /run/lock
tmpfs 507916 0 507916 0% /sys/fs/cgroup
vagrant 343946960 55977016 287969944 17% /vagrant
tmpfs 101584 0 101584 0% /run/user/1000

root@ubuntu-xenial:~# dumpe2fs /dev/sda1 | grep -i block | grep -i size
dumpe2fs 1.42.13 (17-May-2015)
Block size: 4096
Flex block group size: 16


What is more, fdisk command reports different sector size (aren't the terms sector and block interchangeable?)



root@ubuntu-xenial:~# fdisk -l
Disk /dev/sda: 10 GiB, 10737418240 bytes, 20971520 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: dos
Disk identifier: 0x38d40272

Device Boot Start End Sectors Size Id Type
/dev/sda1 * 2048 20971486 20969439 10G 83 Linux


Disk /dev/sdb: 10 MiB, 10485760 bytes, 20480 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes


I am on a vagrant machine for what that matters









share|improve this question












share|improve this question




share|improve this question








edited 16 hours ago
























asked 17 hours ago









pkaramol

252112




252112











  • It would be much easier for people to write a specific answer, if you wrote out a specific sentence with a question mark :-). (You can create followup questions later if needed). blockdev can return three types of block sizes with different values. And grep -H . /sys/class/block/sda/queue/*_block,io_size shows the same 4 different types printed by fdisk. Is your question "Why is there a difference between these two commands?" Is it "how can I see the block size used to allocate space on my filesystem?" Are you looking into something different from space allocation?
    – sourcejedi
    14 hours ago











  • Is your question "What is the difference between the 4 sizes printed by fdisk?" So you can see there's a number of different questions you might have in mind.
    – sourcejedi
    14 hours ago

















  • It would be much easier for people to write a specific answer, if you wrote out a specific sentence with a question mark :-). (You can create followup questions later if needed). blockdev can return three types of block sizes with different values. And grep -H . /sys/class/block/sda/queue/*_block,io_size shows the same 4 different types printed by fdisk. Is your question "Why is there a difference between these two commands?" Is it "how can I see the block size used to allocate space on my filesystem?" Are you looking into something different from space allocation?
    – sourcejedi
    14 hours ago











  • Is your question "What is the difference between the 4 sizes printed by fdisk?" So you can see there's a number of different questions you might have in mind.
    – sourcejedi
    14 hours ago
















It would be much easier for people to write a specific answer, if you wrote out a specific sentence with a question mark :-). (You can create followup questions later if needed). blockdev can return three types of block sizes with different values. And grep -H . /sys/class/block/sda/queue/*_block,io_size shows the same 4 different types printed by fdisk. Is your question "Why is there a difference between these two commands?" Is it "how can I see the block size used to allocate space on my filesystem?" Are you looking into something different from space allocation?
– sourcejedi
14 hours ago





It would be much easier for people to write a specific answer, if you wrote out a specific sentence with a question mark :-). (You can create followup questions later if needed). blockdev can return three types of block sizes with different values. And grep -H . /sys/class/block/sda/queue/*_block,io_size shows the same 4 different types printed by fdisk. Is your question "Why is there a difference between these two commands?" Is it "how can I see the block size used to allocate space on my filesystem?" Are you looking into something different from space allocation?
– sourcejedi
14 hours ago













Is your question "What is the difference between the 4 sizes printed by fdisk?" So you can see there's a number of different questions you might have in mind.
– sourcejedi
14 hours ago





Is your question "What is the difference between the 4 sizes printed by fdisk?" So you can see there's a number of different questions you might have in mind.
– sourcejedi
14 hours ago











3 Answers
3






active

oldest

votes

















up vote
2
down vote



accepted











... reports different sector size (aren't the terms sector and block interchangeable?)




"Block" has been used to mean many different things. You have to look at the specific context.



df stretches this further, saying "1K-blocks" to mean units of 1 Kilobyte, even when the filesystem(s) use different block sizes.



"Sector" originally means the block size a disk uses. But notice your fdisk reports two different types of sector size, "physical" and "logical" :-). So you need to look out for context here as well. [*]



What is the filesystem block size?



Because the first tools you mentioned were df and dumpe2fs, I guessed you might be looking for the filesystem block size. In that case, you want the value which dumpe2fs shows as "Block size".



dumpe2fs is a specific tool for ext2/3/4, but I think that makes for the most robust approach. That said, it means that if you use a different filesystem, you will have to use a different tool and confirm exactly what it uses for "block size".



There may be some exceptions to the normal filesystem block size. Very recent ext4 may support data storage inline in the inode. That is, files smaller than a certain size may be stored in the file's inode, without allocating any data blocks at all. See How to use the new Ext4 Inline Data feature ? (storing data directly in the inode)



Alternative query method: statvfs()



Alternatively, you could run stat -f / to show the statvfs() information for your root filesystem. It was discussed here: stat file system sizes.



stat -f output includes two different fields, "Fundamental block size" and "Block size" :-).



The "fundamental" block size is the granularity that space usage is reported in - this will apply to df. You can hope that this is the same granularity used to allocate file space. At least this is true for your ext2/3/4, and in many other cases.



stat claims the other block size is to be used "for fast transfers". In ext2/3/4, these two block sizes will always be the same.



If ext2 had ever implemented fragments, like UFS from BSD UNIX, it would have been possible for the two sizes to differ. This is reflected in dumpe2fs always showing a "Fragment size" value equal to "Block size". See What can f_bsize be used for? (Is it similar to st_blksize?)



As a more generic tool, stat -f is liable to mislead in some cases.



It is not very widely used either; this might increase the risk. It doesn't help that it reports two different values, where the original meanings are not relevant to native Linux filesystems. FWIW, this site's users hated my question asking to confirm its behaviour (the link above). I usually assume this means they got angry because no-one knows how to answer the question.



stat -f is a feature of GNU coreutils. (It is not supported by stat from FreeBSD 7.2).



Is "block size 'for fast transfers' " meaningful?



This description may be relevant for filesystems which implement fragments. If they do not implement "delayed allocation", it may be more efficient to make sure you use a block-sized write buffer when you increase the length of a file. As always, if you are thinking about making a change to improve performance, you should aim to confirm the improvement with measurements.



On Linux filesystems, the two block sizes will be the same value. In this case, I don't know any reason to use that particular value for optimization.



Most often, userspace doesn't have to worry too much about sizing I/O calls "for fast transfers". The IO scheduler can coalesce adjacent I/Os for efficiency. And un-synced IO through the page cache gets massive performance benefits from write-back caching and automatic read-ahead. You can go a long way just using the page cache size, or hard-coding 4KB :-).



In most transfers, the page cache imposes a minimum size for the physical IO. The page size is 4KB on most systems, and usually file IO goes through the page cache. (Again small files are a special case. Or rather the last page of a file is a special case, if the file size is not an exact multiple of 4KB).




[*] E.g. given modern abstraction layers, you might sometimes see a field that says "sector size" reported as 512, on a modern "advanced format" disk which uses 4KB physical sectors.






share|improve this answer






























    up vote
    4
    down vote













    You don't "get block size via df". That's not shown in the output at all.



    df lists all filesystems, their usage and mountpoints in one list - and the values shown simply refer to sizes (total / used / available) and not other individual properties like filesystem type, blocksize, etc.



    By default, the unit to represent size is 1K-blocks, you can change it to 1M-blocks or 1G-blocks or variable (human-readable).



    $ df
    Filesystem 1K-blocks Used Available Use% Mounted on
    /dev/dm-34 25155584 19811668 5343916 79% /

    $ df --block-size=M
    Filesystem 1M-blocks Used Available Use% Mounted on
    /dev/dm-34 24566M 19348M 5219M 79% /

    $ df --block-size=G
    Filesystem 1G-blocks Used Available Use% Mounted on
    /dev/dm-34 24G 19G 6G 79% /

    $ df -h
    Filesystem Size Used Avail Use% Mounted on
    /dev/dm-34 24G 19G 5.1G 79% /


    (Note the subtle difference -BG and -h is that Available column shows 6G vs. 5.1G. Human-readable size adapts according to size, vs. there is no fraction blocks when using a huge blocksize).



    As for the filesystem, it does not have to work in 512 byte units just because the storage device does. Never mind that a lot of storage has larger sectors these days, but still pretends to be 512 bytes for compatibility reasons.




    aren't the terms sector and block interchangeable?




    Unfortunately, these terms are used in different ways depending on context.






    share|improve this answer




























      up vote
      0
      down vote













      After some digging it turns out that the appropriate way to get block size is



      root@ubuntu-xenial:/proc# blockdev --getbsz /dev/sda
      4096


      It may of course differ from one block device to another.



      In any case the above value seems to be consistent with the output of dumpe2fs






      share|improve this answer

















      • 1




        There is a "fun" qualifier here that you omit. Don't use this on sda1. unless you know exactly what it does. --getbsz is the soft block size. I believe it is guaranteed to be equal to the output of dumpe2fs - once you have mounted that FS. If you haven't mounted the FS (on the current boot), it can show a smaller blocks size (1KB?). unix.stackexchange.com/questions/403919/… In answer to the question, this link defines three different sizes.
        – sourcejedi
        14 hours ago










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      3 Answers
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      3 Answers
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      active

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      active

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      up vote
      2
      down vote



      accepted











      ... reports different sector size (aren't the terms sector and block interchangeable?)




      "Block" has been used to mean many different things. You have to look at the specific context.



      df stretches this further, saying "1K-blocks" to mean units of 1 Kilobyte, even when the filesystem(s) use different block sizes.



      "Sector" originally means the block size a disk uses. But notice your fdisk reports two different types of sector size, "physical" and "logical" :-). So you need to look out for context here as well. [*]



      What is the filesystem block size?



      Because the first tools you mentioned were df and dumpe2fs, I guessed you might be looking for the filesystem block size. In that case, you want the value which dumpe2fs shows as "Block size".



      dumpe2fs is a specific tool for ext2/3/4, but I think that makes for the most robust approach. That said, it means that if you use a different filesystem, you will have to use a different tool and confirm exactly what it uses for "block size".



      There may be some exceptions to the normal filesystem block size. Very recent ext4 may support data storage inline in the inode. That is, files smaller than a certain size may be stored in the file's inode, without allocating any data blocks at all. See How to use the new Ext4 Inline Data feature ? (storing data directly in the inode)



      Alternative query method: statvfs()



      Alternatively, you could run stat -f / to show the statvfs() information for your root filesystem. It was discussed here: stat file system sizes.



      stat -f output includes two different fields, "Fundamental block size" and "Block size" :-).



      The "fundamental" block size is the granularity that space usage is reported in - this will apply to df. You can hope that this is the same granularity used to allocate file space. At least this is true for your ext2/3/4, and in many other cases.



      stat claims the other block size is to be used "for fast transfers". In ext2/3/4, these two block sizes will always be the same.



      If ext2 had ever implemented fragments, like UFS from BSD UNIX, it would have been possible for the two sizes to differ. This is reflected in dumpe2fs always showing a "Fragment size" value equal to "Block size". See What can f_bsize be used for? (Is it similar to st_blksize?)



      As a more generic tool, stat -f is liable to mislead in some cases.



      It is not very widely used either; this might increase the risk. It doesn't help that it reports two different values, where the original meanings are not relevant to native Linux filesystems. FWIW, this site's users hated my question asking to confirm its behaviour (the link above). I usually assume this means they got angry because no-one knows how to answer the question.



      stat -f is a feature of GNU coreutils. (It is not supported by stat from FreeBSD 7.2).



      Is "block size 'for fast transfers' " meaningful?



      This description may be relevant for filesystems which implement fragments. If they do not implement "delayed allocation", it may be more efficient to make sure you use a block-sized write buffer when you increase the length of a file. As always, if you are thinking about making a change to improve performance, you should aim to confirm the improvement with measurements.



      On Linux filesystems, the two block sizes will be the same value. In this case, I don't know any reason to use that particular value for optimization.



      Most often, userspace doesn't have to worry too much about sizing I/O calls "for fast transfers". The IO scheduler can coalesce adjacent I/Os for efficiency. And un-synced IO through the page cache gets massive performance benefits from write-back caching and automatic read-ahead. You can go a long way just using the page cache size, or hard-coding 4KB :-).



      In most transfers, the page cache imposes a minimum size for the physical IO. The page size is 4KB on most systems, and usually file IO goes through the page cache. (Again small files are a special case. Or rather the last page of a file is a special case, if the file size is not an exact multiple of 4KB).




      [*] E.g. given modern abstraction layers, you might sometimes see a field that says "sector size" reported as 512, on a modern "advanced format" disk which uses 4KB physical sectors.






      share|improve this answer



























        up vote
        2
        down vote



        accepted











        ... reports different sector size (aren't the terms sector and block interchangeable?)




        "Block" has been used to mean many different things. You have to look at the specific context.



        df stretches this further, saying "1K-blocks" to mean units of 1 Kilobyte, even when the filesystem(s) use different block sizes.



        "Sector" originally means the block size a disk uses. But notice your fdisk reports two different types of sector size, "physical" and "logical" :-). So you need to look out for context here as well. [*]



        What is the filesystem block size?



        Because the first tools you mentioned were df and dumpe2fs, I guessed you might be looking for the filesystem block size. In that case, you want the value which dumpe2fs shows as "Block size".



        dumpe2fs is a specific tool for ext2/3/4, but I think that makes for the most robust approach. That said, it means that if you use a different filesystem, you will have to use a different tool and confirm exactly what it uses for "block size".



        There may be some exceptions to the normal filesystem block size. Very recent ext4 may support data storage inline in the inode. That is, files smaller than a certain size may be stored in the file's inode, without allocating any data blocks at all. See How to use the new Ext4 Inline Data feature ? (storing data directly in the inode)



        Alternative query method: statvfs()



        Alternatively, you could run stat -f / to show the statvfs() information for your root filesystem. It was discussed here: stat file system sizes.



        stat -f output includes two different fields, "Fundamental block size" and "Block size" :-).



        The "fundamental" block size is the granularity that space usage is reported in - this will apply to df. You can hope that this is the same granularity used to allocate file space. At least this is true for your ext2/3/4, and in many other cases.



        stat claims the other block size is to be used "for fast transfers". In ext2/3/4, these two block sizes will always be the same.



        If ext2 had ever implemented fragments, like UFS from BSD UNIX, it would have been possible for the two sizes to differ. This is reflected in dumpe2fs always showing a "Fragment size" value equal to "Block size". See What can f_bsize be used for? (Is it similar to st_blksize?)



        As a more generic tool, stat -f is liable to mislead in some cases.



        It is not very widely used either; this might increase the risk. It doesn't help that it reports two different values, where the original meanings are not relevant to native Linux filesystems. FWIW, this site's users hated my question asking to confirm its behaviour (the link above). I usually assume this means they got angry because no-one knows how to answer the question.



        stat -f is a feature of GNU coreutils. (It is not supported by stat from FreeBSD 7.2).



        Is "block size 'for fast transfers' " meaningful?



        This description may be relevant for filesystems which implement fragments. If they do not implement "delayed allocation", it may be more efficient to make sure you use a block-sized write buffer when you increase the length of a file. As always, if you are thinking about making a change to improve performance, you should aim to confirm the improvement with measurements.



        On Linux filesystems, the two block sizes will be the same value. In this case, I don't know any reason to use that particular value for optimization.



        Most often, userspace doesn't have to worry too much about sizing I/O calls "for fast transfers". The IO scheduler can coalesce adjacent I/Os for efficiency. And un-synced IO through the page cache gets massive performance benefits from write-back caching and automatic read-ahead. You can go a long way just using the page cache size, or hard-coding 4KB :-).



        In most transfers, the page cache imposes a minimum size for the physical IO. The page size is 4KB on most systems, and usually file IO goes through the page cache. (Again small files are a special case. Or rather the last page of a file is a special case, if the file size is not an exact multiple of 4KB).




        [*] E.g. given modern abstraction layers, you might sometimes see a field that says "sector size" reported as 512, on a modern "advanced format" disk which uses 4KB physical sectors.






        share|improve this answer

























          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted







          ... reports different sector size (aren't the terms sector and block interchangeable?)




          "Block" has been used to mean many different things. You have to look at the specific context.



          df stretches this further, saying "1K-blocks" to mean units of 1 Kilobyte, even when the filesystem(s) use different block sizes.



          "Sector" originally means the block size a disk uses. But notice your fdisk reports two different types of sector size, "physical" and "logical" :-). So you need to look out for context here as well. [*]



          What is the filesystem block size?



          Because the first tools you mentioned were df and dumpe2fs, I guessed you might be looking for the filesystem block size. In that case, you want the value which dumpe2fs shows as "Block size".



          dumpe2fs is a specific tool for ext2/3/4, but I think that makes for the most robust approach. That said, it means that if you use a different filesystem, you will have to use a different tool and confirm exactly what it uses for "block size".



          There may be some exceptions to the normal filesystem block size. Very recent ext4 may support data storage inline in the inode. That is, files smaller than a certain size may be stored in the file's inode, without allocating any data blocks at all. See How to use the new Ext4 Inline Data feature ? (storing data directly in the inode)



          Alternative query method: statvfs()



          Alternatively, you could run stat -f / to show the statvfs() information for your root filesystem. It was discussed here: stat file system sizes.



          stat -f output includes two different fields, "Fundamental block size" and "Block size" :-).



          The "fundamental" block size is the granularity that space usage is reported in - this will apply to df. You can hope that this is the same granularity used to allocate file space. At least this is true for your ext2/3/4, and in many other cases.



          stat claims the other block size is to be used "for fast transfers". In ext2/3/4, these two block sizes will always be the same.



          If ext2 had ever implemented fragments, like UFS from BSD UNIX, it would have been possible for the two sizes to differ. This is reflected in dumpe2fs always showing a "Fragment size" value equal to "Block size". See What can f_bsize be used for? (Is it similar to st_blksize?)



          As a more generic tool, stat -f is liable to mislead in some cases.



          It is not very widely used either; this might increase the risk. It doesn't help that it reports two different values, where the original meanings are not relevant to native Linux filesystems. FWIW, this site's users hated my question asking to confirm its behaviour (the link above). I usually assume this means they got angry because no-one knows how to answer the question.



          stat -f is a feature of GNU coreutils. (It is not supported by stat from FreeBSD 7.2).



          Is "block size 'for fast transfers' " meaningful?



          This description may be relevant for filesystems which implement fragments. If they do not implement "delayed allocation", it may be more efficient to make sure you use a block-sized write buffer when you increase the length of a file. As always, if you are thinking about making a change to improve performance, you should aim to confirm the improvement with measurements.



          On Linux filesystems, the two block sizes will be the same value. In this case, I don't know any reason to use that particular value for optimization.



          Most often, userspace doesn't have to worry too much about sizing I/O calls "for fast transfers". The IO scheduler can coalesce adjacent I/Os for efficiency. And un-synced IO through the page cache gets massive performance benefits from write-back caching and automatic read-ahead. You can go a long way just using the page cache size, or hard-coding 4KB :-).



          In most transfers, the page cache imposes a minimum size for the physical IO. The page size is 4KB on most systems, and usually file IO goes through the page cache. (Again small files are a special case. Or rather the last page of a file is a special case, if the file size is not an exact multiple of 4KB).




          [*] E.g. given modern abstraction layers, you might sometimes see a field that says "sector size" reported as 512, on a modern "advanced format" disk which uses 4KB physical sectors.






          share|improve this answer
















          ... reports different sector size (aren't the terms sector and block interchangeable?)




          "Block" has been used to mean many different things. You have to look at the specific context.



          df stretches this further, saying "1K-blocks" to mean units of 1 Kilobyte, even when the filesystem(s) use different block sizes.



          "Sector" originally means the block size a disk uses. But notice your fdisk reports two different types of sector size, "physical" and "logical" :-). So you need to look out for context here as well. [*]



          What is the filesystem block size?



          Because the first tools you mentioned were df and dumpe2fs, I guessed you might be looking for the filesystem block size. In that case, you want the value which dumpe2fs shows as "Block size".



          dumpe2fs is a specific tool for ext2/3/4, but I think that makes for the most robust approach. That said, it means that if you use a different filesystem, you will have to use a different tool and confirm exactly what it uses for "block size".



          There may be some exceptions to the normal filesystem block size. Very recent ext4 may support data storage inline in the inode. That is, files smaller than a certain size may be stored in the file's inode, without allocating any data blocks at all. See How to use the new Ext4 Inline Data feature ? (storing data directly in the inode)



          Alternative query method: statvfs()



          Alternatively, you could run stat -f / to show the statvfs() information for your root filesystem. It was discussed here: stat file system sizes.



          stat -f output includes two different fields, "Fundamental block size" and "Block size" :-).



          The "fundamental" block size is the granularity that space usage is reported in - this will apply to df. You can hope that this is the same granularity used to allocate file space. At least this is true for your ext2/3/4, and in many other cases.



          stat claims the other block size is to be used "for fast transfers". In ext2/3/4, these two block sizes will always be the same.



          If ext2 had ever implemented fragments, like UFS from BSD UNIX, it would have been possible for the two sizes to differ. This is reflected in dumpe2fs always showing a "Fragment size" value equal to "Block size". See What can f_bsize be used for? (Is it similar to st_blksize?)



          As a more generic tool, stat -f is liable to mislead in some cases.



          It is not very widely used either; this might increase the risk. It doesn't help that it reports two different values, where the original meanings are not relevant to native Linux filesystems. FWIW, this site's users hated my question asking to confirm its behaviour (the link above). I usually assume this means they got angry because no-one knows how to answer the question.



          stat -f is a feature of GNU coreutils. (It is not supported by stat from FreeBSD 7.2).



          Is "block size 'for fast transfers' " meaningful?



          This description may be relevant for filesystems which implement fragments. If they do not implement "delayed allocation", it may be more efficient to make sure you use a block-sized write buffer when you increase the length of a file. As always, if you are thinking about making a change to improve performance, you should aim to confirm the improvement with measurements.



          On Linux filesystems, the two block sizes will be the same value. In this case, I don't know any reason to use that particular value for optimization.



          Most often, userspace doesn't have to worry too much about sizing I/O calls "for fast transfers". The IO scheduler can coalesce adjacent I/Os for efficiency. And un-synced IO through the page cache gets massive performance benefits from write-back caching and automatic read-ahead. You can go a long way just using the page cache size, or hard-coding 4KB :-).



          In most transfers, the page cache imposes a minimum size for the physical IO. The page size is 4KB on most systems, and usually file IO goes through the page cache. (Again small files are a special case. Or rather the last page of a file is a special case, if the file size is not an exact multiple of 4KB).




          [*] E.g. given modern abstraction layers, you might sometimes see a field that says "sector size" reported as 512, on a modern "advanced format" disk which uses 4KB physical sectors.







          share|improve this answer















          share|improve this answer



          share|improve this answer








          edited 3 hours ago


























          answered 15 hours ago









          sourcejedi

          18.2k32475




          18.2k32475






















              up vote
              4
              down vote













              You don't "get block size via df". That's not shown in the output at all.



              df lists all filesystems, their usage and mountpoints in one list - and the values shown simply refer to sizes (total / used / available) and not other individual properties like filesystem type, blocksize, etc.



              By default, the unit to represent size is 1K-blocks, you can change it to 1M-blocks or 1G-blocks or variable (human-readable).



              $ df
              Filesystem 1K-blocks Used Available Use% Mounted on
              /dev/dm-34 25155584 19811668 5343916 79% /

              $ df --block-size=M
              Filesystem 1M-blocks Used Available Use% Mounted on
              /dev/dm-34 24566M 19348M 5219M 79% /

              $ df --block-size=G
              Filesystem 1G-blocks Used Available Use% Mounted on
              /dev/dm-34 24G 19G 6G 79% /

              $ df -h
              Filesystem Size Used Avail Use% Mounted on
              /dev/dm-34 24G 19G 5.1G 79% /


              (Note the subtle difference -BG and -h is that Available column shows 6G vs. 5.1G. Human-readable size adapts according to size, vs. there is no fraction blocks when using a huge blocksize).



              As for the filesystem, it does not have to work in 512 byte units just because the storage device does. Never mind that a lot of storage has larger sectors these days, but still pretends to be 512 bytes for compatibility reasons.




              aren't the terms sector and block interchangeable?




              Unfortunately, these terms are used in different ways depending on context.






              share|improve this answer

























                up vote
                4
                down vote













                You don't "get block size via df". That's not shown in the output at all.



                df lists all filesystems, their usage and mountpoints in one list - and the values shown simply refer to sizes (total / used / available) and not other individual properties like filesystem type, blocksize, etc.



                By default, the unit to represent size is 1K-blocks, you can change it to 1M-blocks or 1G-blocks or variable (human-readable).



                $ df
                Filesystem 1K-blocks Used Available Use% Mounted on
                /dev/dm-34 25155584 19811668 5343916 79% /

                $ df --block-size=M
                Filesystem 1M-blocks Used Available Use% Mounted on
                /dev/dm-34 24566M 19348M 5219M 79% /

                $ df --block-size=G
                Filesystem 1G-blocks Used Available Use% Mounted on
                /dev/dm-34 24G 19G 6G 79% /

                $ df -h
                Filesystem Size Used Avail Use% Mounted on
                /dev/dm-34 24G 19G 5.1G 79% /


                (Note the subtle difference -BG and -h is that Available column shows 6G vs. 5.1G. Human-readable size adapts according to size, vs. there is no fraction blocks when using a huge blocksize).



                As for the filesystem, it does not have to work in 512 byte units just because the storage device does. Never mind that a lot of storage has larger sectors these days, but still pretends to be 512 bytes for compatibility reasons.




                aren't the terms sector and block interchangeable?




                Unfortunately, these terms are used in different ways depending on context.






                share|improve this answer























                  up vote
                  4
                  down vote










                  up vote
                  4
                  down vote









                  You don't "get block size via df". That's not shown in the output at all.



                  df lists all filesystems, their usage and mountpoints in one list - and the values shown simply refer to sizes (total / used / available) and not other individual properties like filesystem type, blocksize, etc.



                  By default, the unit to represent size is 1K-blocks, you can change it to 1M-blocks or 1G-blocks or variable (human-readable).



                  $ df
                  Filesystem 1K-blocks Used Available Use% Mounted on
                  /dev/dm-34 25155584 19811668 5343916 79% /

                  $ df --block-size=M
                  Filesystem 1M-blocks Used Available Use% Mounted on
                  /dev/dm-34 24566M 19348M 5219M 79% /

                  $ df --block-size=G
                  Filesystem 1G-blocks Used Available Use% Mounted on
                  /dev/dm-34 24G 19G 6G 79% /

                  $ df -h
                  Filesystem Size Used Avail Use% Mounted on
                  /dev/dm-34 24G 19G 5.1G 79% /


                  (Note the subtle difference -BG and -h is that Available column shows 6G vs. 5.1G. Human-readable size adapts according to size, vs. there is no fraction blocks when using a huge blocksize).



                  As for the filesystem, it does not have to work in 512 byte units just because the storage device does. Never mind that a lot of storage has larger sectors these days, but still pretends to be 512 bytes for compatibility reasons.




                  aren't the terms sector and block interchangeable?




                  Unfortunately, these terms are used in different ways depending on context.






                  share|improve this answer













                  You don't "get block size via df". That's not shown in the output at all.



                  df lists all filesystems, their usage and mountpoints in one list - and the values shown simply refer to sizes (total / used / available) and not other individual properties like filesystem type, blocksize, etc.



                  By default, the unit to represent size is 1K-blocks, you can change it to 1M-blocks or 1G-blocks or variable (human-readable).



                  $ df
                  Filesystem 1K-blocks Used Available Use% Mounted on
                  /dev/dm-34 25155584 19811668 5343916 79% /

                  $ df --block-size=M
                  Filesystem 1M-blocks Used Available Use% Mounted on
                  /dev/dm-34 24566M 19348M 5219M 79% /

                  $ df --block-size=G
                  Filesystem 1G-blocks Used Available Use% Mounted on
                  /dev/dm-34 24G 19G 6G 79% /

                  $ df -h
                  Filesystem Size Used Avail Use% Mounted on
                  /dev/dm-34 24G 19G 5.1G 79% /


                  (Note the subtle difference -BG and -h is that Available column shows 6G vs. 5.1G. Human-readable size adapts according to size, vs. there is no fraction blocks when using a huge blocksize).



                  As for the filesystem, it does not have to work in 512 byte units just because the storage device does. Never mind that a lot of storage has larger sectors these days, but still pretends to be 512 bytes for compatibility reasons.




                  aren't the terms sector and block interchangeable?




                  Unfortunately, these terms are used in different ways depending on context.







                  share|improve this answer













                  share|improve this answer



                  share|improve this answer











                  answered 16 hours ago









                  frostschutz

                  24.3k14672




                  24.3k14672




















                      up vote
                      0
                      down vote













                      After some digging it turns out that the appropriate way to get block size is



                      root@ubuntu-xenial:/proc# blockdev --getbsz /dev/sda
                      4096


                      It may of course differ from one block device to another.



                      In any case the above value seems to be consistent with the output of dumpe2fs






                      share|improve this answer

















                      • 1




                        There is a "fun" qualifier here that you omit. Don't use this on sda1. unless you know exactly what it does. --getbsz is the soft block size. I believe it is guaranteed to be equal to the output of dumpe2fs - once you have mounted that FS. If you haven't mounted the FS (on the current boot), it can show a smaller blocks size (1KB?). unix.stackexchange.com/questions/403919/… In answer to the question, this link defines three different sizes.
                        – sourcejedi
                        14 hours ago














                      up vote
                      0
                      down vote













                      After some digging it turns out that the appropriate way to get block size is



                      root@ubuntu-xenial:/proc# blockdev --getbsz /dev/sda
                      4096


                      It may of course differ from one block device to another.



                      In any case the above value seems to be consistent with the output of dumpe2fs






                      share|improve this answer

















                      • 1




                        There is a "fun" qualifier here that you omit. Don't use this on sda1. unless you know exactly what it does. --getbsz is the soft block size. I believe it is guaranteed to be equal to the output of dumpe2fs - once you have mounted that FS. If you haven't mounted the FS (on the current boot), it can show a smaller blocks size (1KB?). unix.stackexchange.com/questions/403919/… In answer to the question, this link defines three different sizes.
                        – sourcejedi
                        14 hours ago












                      up vote
                      0
                      down vote










                      up vote
                      0
                      down vote









                      After some digging it turns out that the appropriate way to get block size is



                      root@ubuntu-xenial:/proc# blockdev --getbsz /dev/sda
                      4096


                      It may of course differ from one block device to another.



                      In any case the above value seems to be consistent with the output of dumpe2fs






                      share|improve this answer













                      After some digging it turns out that the appropriate way to get block size is



                      root@ubuntu-xenial:/proc# blockdev --getbsz /dev/sda
                      4096


                      It may of course differ from one block device to another.



                      In any case the above value seems to be consistent with the output of dumpe2fs







                      share|improve this answer













                      share|improve this answer



                      share|improve this answer











                      answered 16 hours ago









                      pkaramol

                      252112




                      252112







                      • 1




                        There is a "fun" qualifier here that you omit. Don't use this on sda1. unless you know exactly what it does. --getbsz is the soft block size. I believe it is guaranteed to be equal to the output of dumpe2fs - once you have mounted that FS. If you haven't mounted the FS (on the current boot), it can show a smaller blocks size (1KB?). unix.stackexchange.com/questions/403919/… In answer to the question, this link defines three different sizes.
                        – sourcejedi
                        14 hours ago












                      • 1




                        There is a "fun" qualifier here that you omit. Don't use this on sda1. unless you know exactly what it does. --getbsz is the soft block size. I believe it is guaranteed to be equal to the output of dumpe2fs - once you have mounted that FS. If you haven't mounted the FS (on the current boot), it can show a smaller blocks size (1KB?). unix.stackexchange.com/questions/403919/… In answer to the question, this link defines three different sizes.
                        – sourcejedi
                        14 hours ago







                      1




                      1




                      There is a "fun" qualifier here that you omit. Don't use this on sda1. unless you know exactly what it does. --getbsz is the soft block size. I believe it is guaranteed to be equal to the output of dumpe2fs - once you have mounted that FS. If you haven't mounted the FS (on the current boot), it can show a smaller blocks size (1KB?). unix.stackexchange.com/questions/403919/… In answer to the question, this link defines three different sizes.
                      – sourcejedi
                      14 hours ago




                      There is a "fun" qualifier here that you omit. Don't use this on sda1. unless you know exactly what it does. --getbsz is the soft block size. I believe it is guaranteed to be equal to the output of dumpe2fs - once you have mounted that FS. If you haven't mounted the FS (on the current boot), it can show a smaller blocks size (1KB?). unix.stackexchange.com/questions/403919/… In answer to the question, this link defines three different sizes.
                      – sourcejedi
                      14 hours ago












                       

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